We consider the following problem: Given a set
S of
n distinct points in the plane, how many edge-disjoint plane straight-line spanning paths can be drawn on
S? Each spanning path must be crossing-free, but edges from different paths are allowed to intersect at arbitrary points. It is known that if the points of
S are in convex position, then
⌊n/2⌋ such paths always exist. However, for general point sets, the best known construction yields only two edge-disjoint plane spanning paths.
In this paper, we prove that for any set
S of at least ten points in general position (i.e., no three points are collinear), it is always possible to draw at least three edge-disjoint plane straight-line spanning paths. Our proof relies on a structural result about halving lines in point sets and builds on the known two-path construction, which we also strengthen: we show that for any set
S of at least six points, and for any two specified points on the boundary of the convex hull of
S, there exist two edge-disjoint plane spanning paths that start at those prescribed points.
Finally, we complement our positive results with a lower bound: for every
n≥6, there exists a set of
n points for which no more than
⌈n/3⌉ edge-disjoint plane spanning paths are possible.